In this activity, you will be finding the greatest common factor of 2 or 3 numbers.

There are 6 problems with two parts to each problem. In the first part, you will find the greatest common factor and drag that number of baskets to the box.

In the second part, you will find the greatest common factor and drag the number of fruits to show what you would have in one basket.

Don’t forget to click the blue ‘check’ button to check it’s correct before moving on to the next slide.

Use the right arrow to move onto the next slide.

Good luck!

Feeling stuck? The number of baskets will be the largest number that both sets of fruit can be divided by. To begin, list all the factors for each number (numbers it can be divided by). Then look for factors that they have in common. The largest number they have in common is how many baskets can be made.

For example, if you have 24 of one fruit and 30 of another fruit, determine what each of these numbers is divisible by. 24 is divisible by 1, 2, 3, 4, 6, 8, 12, and 24. 30 is divisible by 1, 2, 3, 5, 6, 10, 15, and 30. They are BOTH divisible by 2, 3 and 6. The greatest of these is 6. Therefore, you could fill 6 baskets, having an equal number of fruits in each basket.

There are no formulas to use for this math task.